A person sells one more than half of the number of total oranges to first customer, one more than the one third of remaining oranges to second person and one more than the one fifth of the remaining oranges to the third oranges to the third customer. At last he was left with three oranges. What was the total number of oranges he initially had?
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Let he had x oranges. The eqn becomes-
{(4/5[(2/3[(x/2) -1]) -1]) -1} = 3 =》
X = 20