Estimate the total energy of Earth’s orbit in .
Details and Assumptions:
I created this problem for the 2013 UBC Physics Olympics (Problem 2).
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Relevant wiki: Characteristics of Circular Orbits
The Sun and the Earth move in circular paths about their center of mass. However, since the mass of the Sun is so much greater than the mass of the Earth, the center of mass of Earth and Sun lies very close to the Sun, and the radius of the circle that the Sun moves in is very small. Thus, we can approximately consider the Sun to be fixed, and the Earth to be revolving around the Sun.
The potential energy of Earth is given by U = − r G M Earth M Sun .
The kinetic energy of Earth is K = 2 1 M Earth v 2 . The Earth moves with speed v = R G M Sun , therefore the kinetic energy of Earth is K = 2 r G M Earth M Sun .
The total energy is given by E = K + U = − 2 r G M Earth M Sun .
When we substitute the given values, we get E ≈ − 2 . 6 4 × 1 0 3 3 Joules