Short, but is it Sweet?

Probability Level pending

In how many ways can you permute four 1's and fifty 2's such that at least five 2's lie between each pair of 1's?


The answer is 82251.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

After placing 5 5 2 2 's in each of the 3 3 gaps between the 4 4 1 1 's, we have 35 35 2 2 's left to place, in any combination, in the 5 5 available positions, namely before the first 1 1 , in the 3 3 gaps between the 1 1 's, and after the last 1 1 . This is a 'stars and bars' calculation with solution ( 35 + 5 1 35 ) = 82251 \dbinom{35 + 5 - 1}{35} = \boxed{82251} combinations.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...