Ordered Pairs
How many ordered pairs of integers satisfy the equation ?
Two Permutations of the same solution i.e are considered different.
The answer is 36.
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1 solution
Cross Multiplying, We get, m n = 3 0 0 . Now, 3 0 0 = 2 2 ∗ 3 ∗ 5 2 .
Therefore, 300 Can be expressed as a product of 2 or more integers In ( 2 + 1 ) ( 2 ) ( 2 + 1 ) = 1 8 w a y s . This is Because 300 has 18 factors.
But, Because m , n are Integers and -m*-n=mn, Therefore 36 ways are possible.