Ordered triplets
Number Theory
Level
2
Find the no. of ordered triplets(a,b,c) for natural nos. a,b,c such that a.b.c+a.b+b.c+c.a+a+b+c=42
5
2
27
0
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1 solution
If we add 1 to both the sides then we get (a+1).(b+1).(c+1)=43.It is prime no. if we keep any no. say a+1=43 then we get b,c=0.Similarly we get for others.Hence the answer is 0.