Organic

Chemistry Level 2

B B C C D D A A

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1 solution

Prakhar Bindal
Mar 18, 2016

Firstly AlCl3 being a lewis acid will form AlCl4- generating a stable allylic carbocation. Now this carbocation will attack benzene through Electrophilic aromatic substitution (through Arenium ion mechanism) . Now You are doing Hydroboration Oxidation of alkene which follows antimarkovnikov's regioselectivity Hence OH- will attack on that carbon which has more number of hydrogen . Now You are doing acid catalysed dehydration fo alcohol in which again a carbocation will be formed which will again the attack the benzene in the style of Electrophilic aromatic substitution and result in the formation of quite stable (less angle strain) 5 membered cyclic ring! :)

Note-

Rearrangement Does NOT OCCUR in Hydroboration Oxidation as true carbocation does not form.(Proceeds through formation of trialkyl borane followed by its hydrolysis)

Acid catalysed dehydration of alcohol Follows E1 Reaction (Unimolecular Elimination) so true carbocation is formed.

Arenium Ion is a stable Ion which gets stabilised a bit through resonance. Later on it loses a proton to regain aromaticity and follow Huckel's rule. (Arenium ion is Non Aromatic due to non planarity)

Good explanation!!!!!

Gauri shankar Mishra - 5 years, 2 months ago

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Thank you! Would you like to post a solution to my problem a tunnel so long?

Prakhar Bindal - 5 years, 2 months ago

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Sorry not now . Why not you try my problem --holi And please post a solution of https://brilliant.org/problems/adityas-challenges-in-mechanics-2/

Gauri shankar Mishra - 5 years, 2 months ago

In first step, when carbocation forms due to friedl craft's alkylation, rearrangement should occur as after rearrangement we get 5 hyperconjugative structures and if rearrangement is not taking place then only 2 H.C.S are there.

RAJ RAJPUT - 5 years, 2 months ago

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The carbocation formed after rearrangement will be very very unstable (vinylic cation) . also Before rearrangement the carbocation is resonance stabilised and after rearrangement it won't.Resonance moslty (95%) dominates over hyperconjugation. Also the reason for unstability of vinyl cation is that positive charge is located on sp2 carbon which is quite electronegative. because electronegativity is directly proportional to % s character in the hybrid orbital of an atom.

hope it helps :)

Prakhar Bindal - 5 years, 2 months ago

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