Take , and perform the following reactions sequentially.
Reactions
Keep it in red hot tube at
Then add
Then add (1 eqv)
Then add
Then add [2 eqv.]
Then add
Then
Then alcoholic (1 eqv.)
Now input the answer as follows.
First of all check if it is alkane, alkene or alkyne.
Let
X=1 (For Alkane Product)
X=2 (For Alkene Product)
X=3 (For Alkyne Product)
And Let Y= number of carbons in the product.
And Z= Number of Halogens attached to it.
Find the value of
Original.
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Initially reductive ozonolysis yields glyoxal(3 moles)which then is reduced to an alcohol The alcohol(of 2 carbons) is subsequently reduced to an alkene via E1 pathway and the Pd reduction sets up conditions once more for electrophilic halogenation by the cyclic bromonium complex Finally alcoholic KOH causes an E2 reaction Allowing one to conclude X=2,Y=2,Z=1 And we're done