O's in a plane

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The number of non-intersecting O's that can be drawn on a plane is...

Finite Countably Infinite ( ℵ 0 \aleph_0 ) Doubly Uncountably Infinite ( ℶ 2 \beth_2 ) Uncountably Infinite ( ℶ 1 \beth_1 )

Daniel Liu by Daniel Liu , 21, USA

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1 solution

Aman Jaiswal
Jan 19, 2014

Simply there can be infinite O's can drawn inside an O (non intersecting)

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Not only that, but an uncountably infinite number. Let the center of all the circles be ( 0 , 0 ) (0,0) . Now we can let the circles' radii be any positive real number, and where are an uncountably infinite number of positive real numbers, so the answer is uncountably infinite.

Daniel Liu - 7 years, 4 months ago

The question wasn't clear on whether we could change the size of O's. If we cannot, it's countably infinite.

Arnab Acharya - 7 years, 4 months ago

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