Oscillating Charge - Max Kinetic Energy

There is a massive charged particle ( m = 4 k g , q = 2 C ) (m = 4\,kg, q = 2C) at rest at the origin ( x = 0 m ) (x = 0m) at time t = 0 t = 0 . The particle is influenced by an electric field oriented purely in the x x direction. It's value is given by:

E x = 3 sin ( 5 t ) V m E_x = 3\sin(5t) \hspace{0.2cm} \frac{V}{m}

Determine the maximum kinetic energy of the particle (in Joules, to 2 decimal places).

Note: All physical quantities are in standard SI units.


Inspiration .


The answer is 0.72.

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2 solutions

Steven Chase
Oct 21, 2016

Analytical derivation and numerical simulation yield the same result (0.72 Joules).

Prakhar Bindal
Nov 14, 2016

Its very obvious that electric force is varying as restoring force varies in a spring block system.

So maximum velocity is at extreme ie where force changes its direction. its clear force will change direction at t=pi/5 as sin will change its sign

Now use a = qE/ m = dv/dt

Integrate to get v at t= pi/5

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