Oscillation of a spring

Classical Mechanics Level 1

A spring with spring constant 100 100 N/m is fixed on the left wall in the above diagram, with an iron ball tied to other end. If we pull the iron ball by 0.2 0.2 m to the right, and then release it, the motion of the iron ball will be a harmonic oscillation. If the mass of the iron ball is 1 1 kg and the floor is frictionless, what is the period of the harmonic oscillation of the iron ball?

π \pi seconds 0.2 0.2 seconds 4 π 4\pi seconds 0.2 π 0.2\pi seconds

View wiki
Lakshan Dumpa by Lakshan Dumpa , 24, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

4 solutions

Captain Awesome
Mar 23, 2014

The period of a spring undergoing a simple harmonic oscillation is given by T = 2 π m k T = 2\pi\sqrt{\frac{m}{k}} . So with the given above, T = 1 5 π = 0.2 π T = \frac{1}{5}\pi = \boxed{0.2\pi} .

5 Helpful 0 Interesting 0 Brilliant 0 Confused
Cheki Dorji
Mar 31, 2014

Here is another way to find it in detail: Natural frequency of simple harmonic is Sqrt(K/m). And the period of oscillation can be written as (2*Pi)/natural frequency. If in place of period, frequency is asked,you use the first mentioned formula.

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Aashish Patel
Mar 25, 2014

The period of a spring undergoing a simple harmonic oscillation is given by the same formula that captain awesome gave.

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Pranav Kumar
Mar 19, 2014

T=2Pi sqrt { m/k } ,hence,T=0.2Pi s

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...