othmane hr

Algebra Level 1

Given that y 2 4 y 2 + 5 = 0 y^{2} -|4y - 2| + 5 = 0 find the solution!

-3 and -1 8

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1 solution

Callie Ferguson
Oct 28, 2019

There are only two possibilities given for the solution to the equation, so the easy route is to simply plug the given solutions into the equation.

The first possible solution is 8. Plugging 8 into y gives…

8 2 4 ( 8 ) 2 + 5 = 0 8^2 - |4(8)-2| + 5 = 0

64 30 + 5 = 0 64 - |30| + 5 = 0

39 = 0 39 = 0

39 does not equal zero, so this can't be true.

To verify that -3 and -1 are the correct solutions, it's only necessary (in this particular case) to verify that either -3 or -1 is a solution.

Let's use y = 3 y=-3 , for example:

( 3 ) 2 4 ( 3 ) 2 + 5 = 0 (-3)^2 -|4(-3) -2| + 5 = 0

9 14 + 5 = 0 9 - |-14| + 5 = 0

9 14 + 5 = 0 9 - 14 + 5 = 0

0 = 0 0 = 0

Because the equation above is true when -3 is a solution, answer B is correct.

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