The three blue circles with centers and are each tangent to two of the lines making up the triangle and each of them has twice the area of the incircle of the triangle . If the area of the triangle is 1, find the area of the triangle and express it as , where and are positive integers with square-free. Submit your answer as .
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Triangles ABC and XYZ are similar, since the sides of XYZ are parallel to sides of ABC, only distance R (radius of blue circle) over. The ratio of R / r is 2 , from the fact that areas of blue circles are twice the area of the incircle. Therefore the distance CZ is also 2 times the distance OC, where O is the center of the incircle. That makes the distance OZ, along with every other dimension in triangle XYZ, 1 + 2 times the corresponding distances, OC in this case, in triangle ABC. The ratio of the areas is proportional to the square of this figure, that is 3 + 2 2 .