Over n out!!

A battery of 10 V 10V and neglegible internal resistance is connected across the diagonally opposite corners of a cubical network consisting of 12 12 resistors each of 1 Ω 1 \Omega . The current I I flows through the circuit.

Find I I .

I \rightarrow I should be in a m p e r e ampere .

\rightarrow All resistances in the image above are of 1 Ω 1 \Omega and battery is of 10 V 10V .

\rightarrow It's a question from K V P Y KVPY .

Image credit: A k s h a t Akshat S h a r d a Sharda ¨ \ddot \smile


The answer is 12.

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2 solutions

Anand Thakre
Sep 15, 2015

Equivalent resistance will be 5/6 and current will be 60/5 by current = potential/resistance

Good...u can crack kvpy...

Harshu P - 5 years, 9 months ago

HOW???NOT GETTING...PLZ TELL

Mycobacterium Tuberculae - 5 years, 8 months ago

If you understand Hindi, here's a very good video showing the explanation: https://www.youtube.com/watch?v=01Zny2GCA78

But if you don't understand Hindi, here's one in English: https://www.youtube.com/watch?v=PPmPZBtetoc

Vedant Saini - 2 years, 4 months ago
Vedant Saini
Jan 16, 2019

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