One owl hoots every 3 minutes. Another owl hoots every 4 minutes. A third owl hoots every 5 minutes. At how many minutes will all three owls hoot together at the lowest possible time?
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Find the LCM thru prime factorization.
3 = 3
4 = 2 2
5 = 5
Using the set of prime numbers from each set with the highest exponent value, we take
3 × 2 2 × 5 = 6 0