Oxidation state

Chemistry Level 1

What is the oxidation state of sulfur in S X 2 O X 7 X 2 − \ce{S2O7^{2-}} ?

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− 4 -4 + 4 +4 + 5 +5 + 6 +6 + 8 +8

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Sravanth C. by Sravanth C. , 21, India

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4 solutions

Sravanth C.
Jul 17, 2015

Let the oxidation state, of sulphur be x x .

We know that the oxidation state of oxygen is − 2 -2 . Therefore, 2 x + 7 ( − 2 ) = − 2 2 x = − 2 + 14 x = 12 2 x = + 6 2x+7(-2)=-2\\2x=-2+14\\x=\dfrac{12}2\\\boxed{x=+6}

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Moderator note:

Simple standard approach.

Bring on some disproportionate reactions.. they'll be better..

Rishabh Tripathi - 5 years, 11 months ago

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Yeah, after the chem mind maps come up, I'll be posting lots of problems. Thanks for you suggestion.

Sravanth C. - 5 years, 11 months ago

Why is 2x-14=-2?

Mr Yovan - 4 years, 10 months ago

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Because the total charge on the species is -2.

Sravanth C. - 4 years, 10 months ago
Adarsh Mahor
Jul 17, 2015

See x=sulper oxidation state There are 2 molecule of sulpher(x) So,2x Oxidation state of oxygen is -2 So, given- 2x+(-2x7)=(-2) 2x-14=(-2) 2x=14-2 2x=12 X=12/2 X=6

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Arun Kumar
Jan 16, 2019
  • Total oxidation state = charge on S2O7

= -2

Oxidation state of O =-2

Two sulfur molecules present .

Let oxidation state of sulfur be n,

2n + 7*(-2) = -2

2n = 12

n = +6

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Aanchal Shahi
Jan 11, 2016

What is challenge master note and how to post a problem?

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Hi @Aanchal Shahi ! Challenge master note is a brilliant feature, which comes with brilliant 2 ^2 subscription, a challenge master essentially is a professional who gives suggestions to improve the quality of your solution.

You can post a problem by clicking the publish menu(present in the top left corner), where you can post a problem which you think the community will love.

Hope this helps! ⌣ ¨ \ddot\smile

P.S: Please don't ask such questions in the form of answer, post it in Calvin sir's message board .

Sravanth C. - 5 years, 5 months ago

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