Ozonolysis.

Chemistry Level 2

A compound ( C H X 3 ) X 2 C = C H C H = C H C H X 3 \ce { (CH_3)2 C = CH CH = CH CH_3 } undergoes ozonolysis reaction as follows :

( C H X 3 ) X 2 C = C H C H = C H C H X 3 A ( s t a b l e t r i o z o n i d e i n t e r m e d i a t e ) \ce { (CH3)2 C = CH CH = CH CH_3 -> A \ (stable \ triozonide \ intermediate) }

The reagent used in the above reaction is O X 3 \ce {O3} .

A \ce {A} then follows three separate reactions as follows :

1 ) A C H X 3 C O C H X 3 + C H O C H O + C H X 3 C H O 2 ) A C H X 3 C H O H C H X 3 + C H X 2 O H C H X 2 O H + C X 2 H X 5 O H 3 ) A C H X 3 C O C H X 3 + C O O H C O O H + C H X 3 C O O H \begin{aligned} & 1) \ \ce { A -> CH3COCH3 + CHO-CHO + CH3CHO } \\ & 2) \ \ce { A -> CH3CHOHCH3 + CH2OH-CH2OH + C2H5OH } \\ & 3) \ \ce { A -> CH3COCH3 + COOH-COOH + CH3COOH } \end{aligned}

Select the most suitable set of reagents for the above three reactions in the same order as that of the reactions above.

N a B H X 4 , P ( C X 6 H X 5 ) X 3 , K I O X 4 \ce {NaBH4 , P(C6H5)3 , KIO4 } P ( C X 6 H X 5 ) X 3 , L i A l H X 4 , K X 2 C r X 2 O X 7 \ce {P(C6H5)3 , LiAlH4 , K2Cr2O7 } P ( C X 6 H X 5 ) X 3 , ( C H X 3 ) X 2 S , K X 2 C r X 2 O X 7 \ce {P(C6H5)3 , (CH3)2S , K2Cr2O7 } P ( C X 6 H X 5 ) X 3 , L i A l H X 4 , N a B H X 4 \ce {P(C6H5)3 , LiAlH4 , NaBH4 }

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1 solution

In the first reaction, A A is reduced to give aldéhydes ( C H O C H O CHO-CHO and C H 3 C H O CH_{3}CHO ) and ketone , that means reagent must be a weak reductive work-up condition. So answer A is eliminated.

In the second one, A A is converted to alcohols , which can be viewed as the products in reaction (1) under another stronger reductive work-up condition (because the use of triphenylphosphine , thiourea , zinc dust, or dimethyl sulfide produces aldehydes or ketones only). So C is eliminated.

In the final reaction, A A is oxidized to give ketone and carboxylic acids , which is the function of K 2 C r 2 O 7 K_{2}Cr_{2}O_{7} , so the correct answer is B \boxed{B} .

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