An algebra problem by Benedict Dimacutac

From the question, P can be written as

P= $\frac { (16+2)(16-2)(16+3)(16-3).....(16+8)(16-8) }{ 18\times 13\times 19\times 12\times ....24\times 7 }$

$=\frac { 18\times 14\times 19\times 13\times ....\times 23\times 9\times 24\times 8 }{ 18\times 13\times 19\times 12\times ....\times 24\times 7 }$

$=\frac { 14 }{ 7 }$

$=\ { 2 }$