Page of A Book

Level pending

The page numbers of a book sum to 1999 1999 . One page number was counted twice. Which page number was that?

It may be helpful to note that : 1 + 2 + 3 + + ( n 1 ) + n = n ( n + 1 ) 2 1+2+3+\ldots+(n-1)+n=\frac{n(n+1)}{2}


The answer is 46.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Sourav Kumar
Mar 10, 2014

there are 62 pages whose sum is 1953 the page which was recounted was 1999-1953=46th page number

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...