Painting a tetrahedron

Probability Level pending

You have 4 4 different colors, and you wish to paint the 4 4 faces of a regular tetrahedron, each in a different color. How many different ways can you do it?


Note : Different implies that for two coloring combinations A A and B B , you can't pick up A A and reorient it to make it look exactly like B B .

Image credit: http://www.korthalsaltes.com/

2 3 1 5 6 4 8 7

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1 solution

Geoff Pilling
Sep 8, 2016

Suppose the 4 colors are red, green, yellow and blue. Without loss of generality, you can paint the bottom green. Then you really only have two unique choices for the remaining three colors: Going clockwise looking from the top... "red -> yellow -> blue" or "red -> blue -> yellow".

Therefore there are 2 \boxed2 solutions.

Or another way of looking at it, is that you can pick any two sides (without loss of generality) and paint them yellow and blue. This leaves you only 2 \boxed2 choices for the remaining two colors (red and green), which are both "different" as defined in the problem.

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