Pair Me Up!
I have 4 cards, 2 black and 2 white. I have flipped them over and randomly rearranged them.
Each turn, I may pick 2 cards and see whether they have the same colour. If they are, then I get to take the pair of cards. If they are not, then I leave them as they are.
In the worst possible scenario, what is the least number of turns I will need to get both pairs of cards?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
0 solutions
No explanations have been posted yet. Check back later!