Pair of numbers

Algebra Level 2

$\boxed{2A1B}$

$\text{(A+2)-2=0}$

$\text{2}$ $\text{B}^{2}$ = $\text{128}$

Find out which of the following could be the values of $\text{A\&B}$ .

0,0 3,4 1,2 0,8 8,8 0,7

1 solution

Matin Naseri
Feb 15, 2018

First operate:

$\text{(2-2)+A = 0}$

$\text{(0)+A = 0}$

$\text{(0)+0 = 0}$

Thus $\text{0 = A}$

Second operate :

$\text{2}$ $\text{B}^{2}$ = $\text{128}$

$\text{128÷2 = 64}$

A has an exponent of $\text{2}$ thus we get square root from $\text{64}$

$\sqrt{64} = 8$

Conclution:

Thus we have $\text{A = 0, B = 8}$

$\boxed{2018}$

Can we get to 2018 likes??

chase marangu - 3 years, 2 months ago