Groups of three.

From the set of letters { A , B , C , D , E , F , G , H , I , J } \{A, B, C, D, E, F, G, H, I, J\} , how many discrete triplets can be formed?

Try solving without using combinatorics equations.

Clarifications:

  • A triplet is defined to be a group of three letters, for example, ( A , B , C ) (A, B, C) or ( A , C , E ) . (A, C, E).
  • Triplets are discrete when they contain at least one different letter. Triplets such as ( A , B , C ) (A, B, C) and ( A , C , B ) (A, C, B) are not discrete because they contain the same letters but in a different order. Triplets such as ( A , B , C ) (A, B, C) and ( A , B , E ) (A, B, E) , however, are discrete as they contain one different letter.


The answer is 120.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Chew-Seong Cheong
Jul 16, 2017

Relevant wiki: Combinations without Repetition - Basic

The problem is equivalent to choosing three different objects from a set of 10 ( { A , B , C , . . . J } \{A, B, C, ... J\} ). Therefore, the total number of discrete triplets N = ( 10 3 ) = 10 × 9 × 8 3 × 2 = 120 N = \displaystyle {10 \choose 3} = \dfrac {10\times 9 \times 8}{3 \times 2} = \boxed{120} .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...