Palindrome!
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is the number of three digit perfect squares having zero as some of it's digits which, when the positions of the digits are reversed, become perfect squares.
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is the number of three digit palindromic perfect squares, none of whose digits are zero.
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is the number of three digit perfect squares, all of whose digits are distinct and non-zero which, when the positions of the digits are reversed, become perfect squares, being the square of numbers whose digits are also reversed.
Find the value of .
The answer is 36.
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1 solution
a=3 as only 3 numbers satisfy its condition, which are 400, 900 and 100.
b=3 as only 3 numbers satisfy its condition, which are 121, 482, 676.
c=2 as only 2 numbers satisfy its condition, which are 961 and 169.
Hence, (3+3)^2 = 6^2 = 36. I will soon update the solution with proper reasoning or I will post a very easy approach as I'm busy with some college work for now, although you can check the list of squares of numbers from 10 to 31.