Paraboloid - Constrained Maxdist

Calculus Level 3

Consider the truncated paraboloid:

z = x 2 + y 2 0 z 1 z = x^2 + y^2 \\ 0 \leq z \leq 1

Let P 1 \vec{P}_1 and P 2 \vec{P}_2 be two points on the truncated paraboloid, subject to the following constraint:

P 2 P 1 = α v v = ( v x , v y , v z ) = ( 3 , 1 , 2 ) α = a real number \vec{P}_2 - \vec{P}_1 = \alpha \, \vec{v} \\ \vec{v} = (v_x,v_y,v_z) = (3,1,2) \\ \alpha = \,\, \text{a real number}

Given the constraints, what is the maximum possible distance between P 1 \vec{P}_1 and P 2 \vec{P}_2 ?


The answer is 1.618.

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