Parallel Plates: Part 1

Consider two parallel, grounded, conducting plates located at x = L x=-L and x = L x=L . Two charges of Q + = 92 μ C Q_{+}=92 \space \mu C and Q = 92 μ C Q_{-}=-92 \space \mu C are placed at ( L / 2 , 0 , 0 ) (-L/2,0,0) and ( L / 2 , 0 , 0 ) (L/2,0,0) respectively. What is the total charge induced on the plate located at x = L x=L in microcoulombs?


The answer is 46.

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1 solution

Jonathan Schirmer
Jan 29, 2014

Take a look at the plane x = 0 x=0 . Clearly the the voltage everywhere on this plane is zero. We can imagine replacing the plane x = 0 x=0 by another grounded plate, and the problem will be equivalent!

Let's do that. Consider the problem of a charge Q = 92 μ C Q=-92 \space \mu C located at ( L / 2 , 0 , 0 ) (L/2,0,0) surrounded by two parallel, grounded, conducting plates located at x = 0 x=0 and x = L x=L . By symmetry, the induced charge on these plates should be the same. Furthermore, the combined induced charge on both of the plates should be 92 μ C 92 \space \mu C . Now we can see that the induced charge on the plate at x = L x=L should be 92 2 μ C = 46 μ C \frac{92}{2} \space \mu C = 46 \space \mu C . But remember that this problem is equivalent to our original problem! Therefore the answer is 46 μ C \boxed{46 \space \mu C} .

Hi Jonathan, great solution! I wanted to confirm. This is the first time I am learning this concept, am I right in saying that the middle plate you have assumed will have no charge on it, since the individual induced charges cancel each other? Please correct me if I am wrong.

Rohan Rao - 7 years, 3 months ago

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