A parametric equation is a way of representing a relationship between two variables (say, x and y ) by introducing a third variable, say t , and setting up a set of equations as a function of this third variable.
Suppose we have the following equation of an ellipse:
x 2 + 4 y 2 = R 2 .
Which set of parametric equations will trace out a similar ellipse?
A. x ( t ) = R cos ( t ) , y ( t ) = 2 R sin ( t )
B. x ( t ) = R sin ( t ) , y ( t ) = 2 R cos ( t )
C. x ( t ) = R cos ( t ) , y ( t ) = 2 R sin ( t )
D. x ( t ) = 2 R cos ( t ) , y ( t ) = R sin ( t )
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Why not B? Also, is the curve supposed to be similar (proportional) or actually identical? I said "three of these" because A,B, and D gave curves with the semi-major axis (x) twice as long as the semi-minor axis (y).
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Yes. A and B are the correct answers. I had a typo in my original solution that I've fixed.
@Steven Chase, B is also included as an answer - see the last line of the Solution explanation.
I think the question actually asks for the curve that is identical to the provided equation of an ellipse as if otherwise, you could even say C is also an answer - it is just D rotated by 90 degrees!
Imagine a right triangle with side lengths x , 2 y and R , and acute angles t 1 and t 2 .
We can then see that:
x = R cos ( t 1 ) y = 2 R sin ( t 1 )
And from the other angle:
x = R sin ( t 2 ) y = 2 R cos ( t 2 )
Which are ellipses congruent to the one given, so the correct answers are A and B.
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If you trace out A and B , for t : 0 → 2 π then you get the ellipse:
x 2 + 4 y 2 = R 2
If you trace out C , for t : 0 → 2 π then you get the ellipse:
x 2 + 4 y 2 = R 2
If you trace out D , for t : 0 → 2 π then you get the ellipse:
4 x 2 + y 2 = R 2
Therefore, A and B both trace out the ellipse we want, so that's two of these .