Parametric Equation Anyone?

Calculus Level 2

A parametric equation is a way of representing a relationship between two variables (say, x x and y y ) by introducing a third variable, say t t , and setting up a set of equations as a function of this third variable.

Suppose we have the following equation of an ellipse:

x 2 + 4 y 2 = R 2 . x^2 + 4y^2 = R^2.

Which set of parametric equations will trace out a similar ellipse?

A. x ( t ) = R cos ( t ) , y ( t ) = R sin ( t ) 2 x(t) = R\cos(t), y(t) = \frac{R\sin(t)}{2}

B. x ( t ) = R sin ( t ) , y ( t ) = R cos ( t ) 2 x(t) = R\sin(t), y(t) = \frac{R\cos(t)}{2}

C. x ( t ) = R cos ( t ) , y ( t ) = 2 R sin ( t ) x(t) = R\cos(t), y(t) = 2R\sin(t)

D. x ( t ) = 2 R cos ( t ) , y ( t ) = R sin ( t ) x(t) = 2R\cos(t), y(t) = R\sin(t)

A B C D Two of these Three of these All of these None of these

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2 solutions

Geoff Pilling
Dec 31, 2016

If you trace out A and B , for t : 0 2 π t: 0 \rightarrow 2\pi then you get the ellipse:

x 2 + 4 y 2 = R 2 x^2 + 4y^2 = R^2

If you trace out C , for t : 0 2 π t: 0 \rightarrow 2\pi then you get the ellipse:

x 2 + y 2 4 = R 2 x^2 + \frac{y^2}{4} = R^2

If you trace out D , for t : 0 2 π t: 0 \rightarrow 2\pi then you get the ellipse:

x 2 4 + y 2 = R 2 \frac{x^2}{4} + y^2 = R^2

Therefore, A and B both trace out the ellipse we want, so that's two of these \boxed{\text{two of these}} .

Why not B? Also, is the curve supposed to be similar (proportional) or actually identical? I said "three of these" because A,B, and D gave curves with the semi-major axis (x) twice as long as the semi-minor axis (y).

Steven Chase - 4 years, 5 months ago

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Yes. A and B are the correct answers. I had a typo in my original solution that I've fixed.

Geoff Pilling - 4 years, 5 months ago

@Steven Chase, B is also included as an answer - see the last line of the Solution explanation.

I think the question actually asks for the curve that is identical to the provided equation of an ellipse as if otherwise, you could even say C is also an answer - it is just D rotated by 90 degrees!

Jel A - 2 years, 4 months ago
Lara Vrabac
Apr 7, 2020

Imagine a right triangle with side lengths x , 2 y x, 2y and R R , and acute angles t 1 t_1 and t 2 t_2 .

We can then see that:

x = R cos ( t 1 ) x=R\cos(t_1) y = R 2 sin ( t 1 ) \\y=\dfrac{R}{2}\sin(t_1)

And from the other angle:

x = R sin ( t 2 ) x=R\sin(t_2) y = R 2 cos ( t 2 ) \\y=\dfrac{R}{2}\cos(t_2)

Which are ellipses congruent to the one given, so the correct answers are A and B.

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