Parametric Tangent

Calculus Level pending

Find the parametric equation of the tangent line to the curve:

x = s i n ( t ) y = c o s ( t ) , z = t x= sin(t) y= cos(t), z= t

at t = π 4 t =\frac {π}{4} .

((Please, do the Favour of Providing a Solution if you are able to Solve))

x ( t ) = s i n ( t ) + 1 2 , y ( t ) = c o s ( t ) − 1 2 , z = t + 1 2 x(t) = sin(t) + \frac{1}{2}, y(t) = cos(t) - \frac{1}{2}, z=t + \frac{1}{2} x ( t ) = s i n ( t ) − 1 2 , y ( t ) = c o s ( t ) + 1 2 , z = t − 1 2 x(t) = sin(t) - \frac{1}{2}, y(t) = cos(t) + \frac{1}{2}, z = t - \frac{1}{2} x ( t ) = ( 1 − t ) / s q r t 2 , y ( t ) = ( 1 + t ) 2 , z = π 4 + t 2 x(t) = \frac{( 1-t)}{/sqrt{2}}, y(t) = \frac{(1+t)}{\sqrt{2}}, z = \frac{π}{4} + \frac{t}{2} x ( t ) = ( 1 + t ) 2 , y ( t ) = ( 1 − t ) 2 , z ( t ) = π 4 + t x(t) = \frac{(1+t)}{\sqrt{2}}, y(t) = \frac{(1-t)}{\sqrt{2}}, z(t) = \frac {π}{4} + t

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Pranav Gupta by Pranav Gupta , 25, India

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