Suppose there is an even function . Is it possible that was also an odd function?
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For any n ∈ N , let S be a set of real numbers such that: S = i = 1 ⋃ n S i , where S i = [ l i , r i ) , l 1 ≥ 0 and l i < r i ≤ l i + 1 . Let: S = i = 1 ⋃ n S i , where S i = ( − r i , − l i ] . Now, let: X = S ∪ S . Any function f ( x ) defined on X such that f : X → { 0 } is both odd and even, since f ( x ) = f ( − x ) = − f ( − x ) = 0 , ∀ x ∈ X .