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This is because we note that the denominator of x 3 7 is odd, which means the function is defined for all x ∈ R , not just x ∈ R +
If we take the cube root of a negative number, then the cube root will remain real. Therefore, we can eliminate A and C. We can eliminate B because x → ∞ lim B ′ ( x ) = 0 (meaning the graph's rate of change gets smaller and smaller); in x 3 7 , this is not the case. Therefore, the answer is D. β ⌈ ∣ ⌉
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Actual graph is