Pascal

Algebra Level 3

True or False?

The concatenation of the digits of the n th n^\text{th} row of the Pascal's triangle is equal to 1 1 n 11^n for all non-negative integers n n .

False True

Harshit Mittal by Harshit Mittal , 23, India

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1 solution

Harshit Mittal
Sep 6, 2016

It Is Actually The Solution to 1 1 n − 1 11^{n-1}
1 s t 1^{st} Term = 1 1 0 11^0 = 1
2 n d 2^{nd} Term = 1 1 1 11^1 = 11
.
.
6 t h 6^{th} Term = 1 1 5 11^5 = 1 (5+1) (0+1) 0 5 1 = 161051

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Could have been worded better. I interpret the answer as the sum of each row not being 1 1 n 11^n .

i. e. 1 = 1 1 = 1

1 + 1 = 2 1 + 1 = 2

1 + 2 + 1 = 4 1 + 2 + 1 = 4

And so on.

Goh Choon Aik - 4 years, 9 months ago

Not Understood!

Harshit Mittal - 4 years, 9 months ago

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