Pass or Fail?

Let x = students who passed the exam

let y = students who failed the exam

in the first ratio:

(x/y) = 4/1 (equation 1)

in the second ratio:

(x-20)/(y-10) = 5/1 (equation 2)

solving for x and y, you will get x = 120 and y = 30

total of students = x + y = 120 + 30 = 150

P:F=4:1 so P = 4x, F = x accordingly, (4x-20):((5x-30)-(4x-20)) = 5:1, solving x =30 so T = 150

passed for x is 4x/5(ratio 4:1). passed for x-30 is 5(x-30)/6(ratio 5:1). After that we have to solve the equation (4x/5)-20=5(x-30)/6.The required solution is x.

Let x be the no. Of students failed Therefore, according to the ratio 4x passed. Hence total no. Of students are x+4x= 5x According to the question, new total students= 5x-30 Passed=4x-20 Failed=(5x-30)-(4x-20)=x-10 Hence given ratio= (4x-20)/(x-10)=5/1 Therefore, x= 30 Total students= 5x =5*30=150 ans.

let number of student pass =4x and fail =1x total number of apperead =5x .. now no of pased students =4x-20 and total students and total number of students 5x-30 no of passssed students = 5x-30-(4x-20) = x-10 now 4x-20/x-10=5/1 solving we get x=30 total number of students =5x thats 5x30=150

Let, students who fail = x, So Students who passed = 4x and total student = 4x+x = 5x Now (4x-20)/(x-10) = 5/1 ie. x = 30. So total students = 5*30 = 150.

In first case: P:F=4:1 T=P+F, ==> so F=T-P Hence, P:T-P=4:1

This equation can be reduced to T=4/5*P ,............................................(1)

In second case: P-20:(T-30)-(P-20)=5:1 ................................................(2)

put the value of from equation (1) in equation (2), and solving for T,

we get T=150.

1/6=X/20

x=120 Since 30 fewer students then the total students who take the exam is 120+30= 150

pass= 120 failed= 30

Let S number of success student F number of failed students s/F = 4 S-20 / F-10 = 5. Number of success decreased by 20 and failed decreased by 10.

Solve to equations in s f.
S=120 F=30 Total student 150