Let
be a triangle in which
. Suppose the
orthocenter
of the triangle lies on the incircle, find the ratio
.
If this ratio can be expressed as , where and are coprime positive integers, submit your answer as .
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Let G be the midpoint of DC. Join G to I, the in-centre and extend it to meet AB in J. We note that GI//CH and thus meets AB at a right angle. Moreover, J is thus the point of tangency of the in-circle with side AB. We further claim that triangles BGJ & ABD are similar and therefore, AB/BD = BG/BJ =BG/BD. Thus, AB=BG=BC/2+BC/4=(3/4)BC which yields, AB/BC = 3/4 or p+q =7..