Passing Through a Sphere

Consider a spherical region with radius 1 m 1 \, \text{m} centered on ( x , y , z ) = ( 2 , 3 , 5 ) m (x,y,z) = (2,3,5) \, \text{m} . A projectile is launched from the origin with a speed of 20 m/s 20 \, \text{m/s} . The projectile enters the sphere and then leaves it at ( x , y , z ) = ( 2 , 3 , 6 ) m (x,y,z) = (2,3,6) \, \text{m} .

If gravity is 10 m/s 2 10 \, \text{m/s}^2 in the negative- z z direction, how much time (in seconds) does the projectile spend within the sphere?


The answer is 0.09737.

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1 solution

Otto Bretscher
Dec 1, 2018

Since the projectile moves in the plane 3 x = 2 y 3x=2y , it is convenient to introduce a u , v u,v coordinate system with orthonormal basis 1 13 ( 2 , 3 , 0 ) , ( 0 , 0 , 1 ) \frac{1}{\sqrt{13}}(2,3,0),(0,0,1) . The path of the projectile is of the form u = 20 ( cos θ ) t , v = 20 ( sin θ ) t 5 t 2 u=20(\cos\theta) t, v=20 (\sin\theta) t-5t^2 . The smaller solution of u = 13 , v = 6 u=\sqrt{13},v=6 is t 0.3817 , θ = 1.0789 t\approx 0.3817,\theta=1.0789 . The other solution of ( u 13 ) 2 + ( v 5 ) 2 = 1 (u-\sqrt{13})^2+(v-5)^2=1 is t 0.2843 t\approx 0.2843 , so that the answer is Δ t 0.0974 \Delta t\approx 0.0974 .

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