At the moment at which they are passing each other, both moving trains are 200ft apart from one another (distance separating the two parallel tracks). If Train A is traveling East at 50 ft/sec and Train B is traveling West at 10ft/sec, how far apart will the Trains be after 9 seconds?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
At the moment they are passing we get a situation like the one presented to us in the diagram. Since train a is moving 50 ft/sec it will have traveled 450 ft to the East after 9 seconds. Similarly Train b has traveled 90 ft to the West during that time. We can construct a triangle and use the Pythagorean theorem to solve for the final distance between A and B after 9 seconds:
b = 4 5 0 + 9 0 = 5 4 0 a = 2 0 0 h y p = a 2 + b 2 = 5 7 5 . 8 5