Past, present and future

Let,

$\begin{aligned} n & = \frac{\text{ln }2014}{\log 2014 }+\frac{\log 2015 }{\text{ln }2015} \\ & = \frac{\frac{\log 2014 }{\log e}}{\log 2014 }+\frac{\log 2015 }{\frac{\log 2015 }{\log e }} \\ & = \frac{1}{\log e}+\log e \end{aligned}$

And,

$\begin{aligned} m & = \frac{\text{ln }2017}{\log 2017 }+\frac{\log 2016 }{\text{ln }2016} \\ & = \frac{\frac{\log 2017 }{\log e}}{\log 2017 }+\frac{\log 2016 }{\frac{\log 2016 }{\log e }} \\ & = \frac{1}{\log e}+\log e \end{aligned}$

Now, we can see that $n=m$ .