Pastries

Both John and Paul like pastries, but they realize that they haven't got enough money: to buy one pastry, Paul needs more 53 cents and John needs more 48 cents. Even if they put together their money they can't buy one pastry.

With this information you can't know unambiguously the cost of a single pastry, but you can get the maximum cost of a pastry. Write this cost in dollars .


The answer is 1.00.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Paudel Ashish
Mar 12, 2014

let x be the cost of a pastry in dollars.

then, cost of pastry in cents = 100x let y be the money with 1st guy(i forgot his name) in cents and z be the money with 2nd guy. then, by question.... y+53=100x----(i) and z+48=100x----(ii) also by question.... y+z<100x [since they cant buy a single pastry even if they add their money] now adding (i) and (ii), y+z+101=200x thus, y+z=200x-101 then, 200x-101<100x thus, 100x<101 so...x<1.01

Animesh Mishra
Feb 24, 2014

its really simple we have got two equations

P+53=C...........a where C is the cost of cake and P is money with paul(or whatever his name is)

Secondly, we get:

J+48=C ............b where J is the amount with John

we have got an inequality that

P+J<C.................x

the least value of C to satisfy the equation a and b is 54

now you just increase the value of C by 1 and find the value of J and P

add J and P and see whether it satisfies equation x or not

do this tedious process and ultimately you will get the value of C as 100 cents

which will satisfy equation x

why least value of C is 54????

vedika rathi - 7 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...