Pattern recognition ...

Logic Level 2

Find the next term of the given sequence.

15 , 49 , 201 , 1011 , 6073 , 42519 , 15, 49, 201, 1011, 6073, 42519, __

340170 92658 257587 340161 257593

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2 solutions

Richard Desper
May 21, 2020

How to get to the solution?

One of the first things I did was to look at the ratios of successive terms. Letting ( ( a n ) ) ((a_n)) denote the sequence, I saw

a 2 a 1 3 \frac{a_2}{a_1} \approx 3 ,
a 3 a 2 4 \frac{a_3}{a_2} \approx 4 , ...
a 6 a 5 7 \frac{a_6}{a_5} \approx 7 .

So this thing is growing super-exponentially. But the ratio of successive terms is growing almost linearly.

Next idea is to consider the differences ( a n ( n + 1 ) a n 1 ) (a_{n} - (n+1)a_{n-1}) to see how close this idea is:

a 2 3 a 1 = 4 a_2 - 3a_1 = 4 ,
a 3 4 a 2 = 5 a_3 - 4a_2 = 5 ,
a 4 5 a 2 = 6 a_4 - 5a_2 = 6 , etc.

This suggests the recursive formula a n = ( n + 1 ) a n 1 + ( n + 2 ) a_n = (n+1)a_{n-1} + (n+2) , initialized with a 1 = 15 a_1 = 15 . This relation works for all six numbers given.

In particular, if we extend this to n = 7 n=7 :

a 7 = 8 a 6 + 9 = 8 42519 + 9 = 340161 a_7 = 8 a_6 + 9 = 8*42519 + 9 = 340161

Nikolas Кraj
May 21, 2020

The pattern of the form a x + a + 1 ax + a + 1 where a a increments by one each step. Here starts with a = 3 a=3 . In the end:

42519 × 8 + 9 = 340161 \boxed {42519 \times 8 + 9 = 340161}

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