Patterns of Win-Loss

Consider the wins to be red marbles and the losses to be blue marbles. In total we have 8 marbles - 5 red and 3 blue. Suppose all the marbles were different, then the number of ways we can arrange them is $8!$ . However this does not include that 5 red marbles are repeated (identical) and 3 blue marbles are repeated. When we include that we get

$\frac{8!}{5!3!} = 56$

8!/3!*5!

8!/(5! * 3!) = 56