Paxxenger's problem
Algebra
Level
3
how many numbers appear in both number sequences?
1, 3, 5, 7, 9, ...,2003.
1, 8, 15, 22, 29, ...,2003.
The answer is 144.
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1 solution
analysis: In the 2nd sequence, every alternate number is odd. Solution: Total number of terms (2003 - 1) / 7 +1 = 287 (287 - 1) / 2 + 1 = 144 There are 144 such numbers -by the books Math olympiad: The next lap-