The peanut-shaped figure below (in black) consists of four circular arcs with each radius labeled on the dashed segments.
What is the perimeter of the peanut-shaped figure rounded to the nearest whole number?
Note : The blue and green dashed segments are not part of the figure.
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If anyone's curious, the area of the peanut is: 2 × ( 4 3 × π × 2 2 ) + ( 9 − 2 1 × π × 1 2 ) = 6 π + 9 − 2 1 π ≈ 2 6
I did not read the problem at first and found the area instead of the perimeter! :P
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The circular arcs at the top and bottom are each 4 3 of a circle with radius 2 . The circumference of the whole circle is 4 π , and so the length of each of these arcs is 3 π .
The circular arcs at the left and right are each 4 1 of a circle with radius 1 . The circumference of the whole circle is 2 π , and so the length of each of these arcs is 2 π .
The total perimeter is 7 π .
If you know that π ≈ 7 2 2 , then it is easy to see that 7 π ≈ 2 2 . However, a calculation by hand will also show you that 7 × 3 . 1 4 = 2 1 . 9 8 , which rounds to 2 2 .