Peanut Perimeter

Geometry Level 2

The peanut-shaped figure below (in black) consists of four circular arcs with each radius labeled on the dashed segments.

What is the perimeter of the peanut-shaped figure rounded to the nearest whole number?

Note : The blue and green dashed segments are not part of the figure.


The answer is 22.

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2 solutions

Andy Hayes
Apr 15, 2016

The circular arcs at the top and bottom are each 3 4 {\large\frac{3}{4}} of a circle with radius 2 2 . The circumference of the whole circle is 4 π 4\pi , and so the length of each of these arcs is 3 π 3\pi .

The circular arcs at the left and right are each 1 4 {\large\frac{1}{4}} of a circle with radius 1 1 . The circumference of the whole circle is 2 π 2\pi , and so the length of each of these arcs is π 2 {\large\frac{\pi}{2}} .

The total perimeter is 7 π 7\pi .

If you know that π 22 7 \pi\approx{\large\frac{22}{7}} , then it is easy to see that 7 π 22 7\pi\approx\boxed{22} . However, a calculation by hand will also show you that 7 × 3.14 = 21.98 7\times 3.14=21.98 , which rounds to 22 \boxed{22} .

Kexin Zheng
Apr 21, 2016

If anyone's curious, the area of the peanut is: 2 × ( 3 4 × π × 2 2 ) + ( 9 1 2 × π × 1 2 ) = 6 π + 9 1 2 π 26 2\times(\frac{3}{4}\times\pi\times 2^{2}) + (9- \frac{1}{2}\times\pi\times 1^{2}) = 6\pi + 9 - \frac{1}{2}\pi \approx 26

I did not read the problem at first and found the area instead of the perimeter! :P

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