A simple pendulum with time period of oscillation equal to 17.32 seconds on the Earth is set into Simple Harmonic motion on Planet X where it weighs one third of its weight on the Earth. What is the Time period of oscillation of the pendulum on Planet X. Assume that there is no loss of energy due to Friction or air resistance where applicable. Round off your answer to the nearest integer
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T = 2π × √(L/g) g on Planet X is g/3 , so T on Planet X is V3 times T on Earth or T on Planet X = 17.32* 1.732 =30 seconds