Percentage error in time period of a pendulum

The bob of a pendulum is released with an amplitude θ = 9 0 o . \theta = 90^{o}. Find the percentage error in the time period of the simple pendulum, if it is calculated by approximating the pendulum to a simple harmonic oscillator.

Assumptions \textbf{Assumptions}

Length of the pendulum = 2 m \rightarrow \text{Length of the pendulum}=2m

g = 9.8 m s 2 \rightarrow g=9.8\frac{m}{s^2}

Friction and drag forces are absent. \rightarrow\text{Friction and drag forces are absent.}


The answer is 15.278.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...