Inverse Percentages?

Algebra Level 2

If A's salary is $33 \dfrac{1}{3}\%$ more than B's, how much is B's salary less than A's?

20\%

25\%

33\frac{1}{3}\%

66\frac{2}{3}\%

1 solution

Hung Woei Neoh
Jun 30, 2016

$A$ has $33\dfrac{1}{3}\%$ more salary than $B\implies$ $A$ has $\dfrac{1}{3}$ more salary than $B$

$A = B + \dfrac{1}{3}B = \dfrac{4}{3}B \implies B = \dfrac{3}{4}A = A - \dfrac{1}{4}A$

$B$ has $\dfrac{1}{4}$ less salary than $A\implies$ $B$ has $\boxed{25\%}$ less salary than $A$