Perfect Divisors

A = 1 ! × 2 ! × 3 ! × × 17 ! A = 1!\times2!\times3!\times\ldots \times17!

Calculate the number of positive divisors of A A which are perfect squares . What are the last two digits of this number?


The answer is 40.

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1 solution

Sakshi Rathore
Mar 25, 2016

I will not waste your time in reading a long solution......you may first try this and then look at its elegant solution......

be brilliant believe on solving on your own....:D

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