Perfectly inelastic collision

Classical Mechanics Level 2

In the above figure, two objects $A$ and $B$ with the same mass $m$ are $15$ m away from each other. Now, $A$ and $B$ are thrown horizontally at the same time at the velocities $20$ m/s and $-10$ m/s, respectively, eventually colliding with each other in the air. If the two objects stick together after a perfectly inelastic collision, what is the speed of the mass at the moment of collision (in m/s)?

Assume that gravitational acceleration is $g= 10$ m/s $^{2}$ .

5 \sqrt{2}

5.0

2 \sqrt{5}

2.5

1 solution

Akash Kumar
Jul 11, 2014

applying conservation of momentum in both horizontal and vertical direction ...as hori. vel. doesn't changes so vel. of combined mass will be (m 20-m 10)/2m= 5 and for vert. velo. fst we have to calculate time which is 0.5 sec as per eqn. (20 t+10 t)=15,, now vert. vel. of both mass =g*t=5 ,,,so applying the very fst equation again we get vel. vert. of combined mass =5.. hence total mass is sqrt of (5.^2+5.^2)= 5root2...answer

Perfectly inelastic collision

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