Perfect square?

A postive integer has five distinct even digits. This number is a perfect square.

Is this possible?

Yes, it's possible. No, it is not possible

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Áron Bán-Szabó
Aug 22, 2017

There are five even digits: 0, 2, 4, 6 and 8. So if it possible, then the digits of the number are 0, 2, 4, 6, and 8 in some order. The sum of the digits is 20. Since 20 2 m o d 3 20\equiv 2 \ \mod 3 , the number (if there is such a number) makes two remainder, when it is divided by 3. However a perfect square never makes 2 remainder, when it is divided by 3.

Therefore it is not possible.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...