Perfect square and perfect cube

What is the sum of all 7-digit numbers that are both a perfect square and a perfect cube?


The answer is 18113890.

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1 solution

Maria Kozlowska
Jan 8, 2016

For a number to be both a perfect square and a perfect cube it needs to be in a form of k 6 k^6 where k is an integer.

k 6 = ( k 3 ) 2 = ( k 2 ) 3 k^6=(k^3)^2=(k^2)^3

The list of k values that satisfy the conditions given are: 10 , 11 , 12 , 13 , 14 10, 11, 12, 13, 14 therefore the sum of k 6 k^6 is 18113890.

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