Perimeter

Geometry Level pending

The ratio of the interior angles of a triangle is 1 : 3 : 5 1:3:5 . If the shortest side is 10 m 10~m , which of the following is the perimeter of the triangle to the nearest integer?

56 m 80 m 97 m 64 m 72 m 39 m 29 m

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1 solution

Since the ratio is 1 : 3 : 5 1:3:5 , the total is 1 + 3 + 5 = 9 1+3+5=9 . The angles are

1 9 ( 180 ) = 2 0 , \dfrac{1}{9}(180)=20^\circ, 3 9 ( 180 ) = 6 0 \dfrac{3}{9}(180)=60^\circ and 5 9 ( 180 ) = 10 0 \dfrac{5}{9}(180)=100^\circ

the shortest side is opposite the smallest angle

By sine rule ,

x sin 60 = 10 sin 20 \dfrac{x}{\sin 60}=\dfrac{10}{\sin 20} \implies x = 10 ( sin 60 sin 20 ) x=10\left(\dfrac{\sin 60}{\sin 20}\right)

By sine rule again,

y sin 100 = 10 sin 20 \dfrac{y}{\sin 100}=\dfrac{10}{\sin 20} \implies y = 10 ( sin 100 sin 20 ) y=10\left(\dfrac{\sin 100}{\sin 20}\right)

Finally, the perimeter is

P = 10 + 10 ( sin 60 sin 20 ) + 10 ( sin 100 sin 20 ) = 10 + 25.32 + 28.79 64 m P=10+10\left(\dfrac{\sin 60}{\sin 20}\right)+10\left(\dfrac{\sin 100}{\sin 20}\right)=10+25.32+28.79\approx64~m

Did the same. 1 typo by the way. When first applying sine rule it's 10/sin(20) instead of 10/sin(60).

Peter van der Linden - 4 years ago

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