Perimeter from Area

Geometry Level 1

The length of a rectangle is three times of its width. If the area of the rectangle is 300 m 2 300 \text{ m}^2 , what is the perimeter of the rectangle (in m \text{m} )?


The answer is 80.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Emmanuel David
Mar 29, 2015

Application of Quadratic Equation

L e n g t h × W i d t h = A r e a Length \times Width = Area

3 x × x = 300 3x \times x = 300

3 x 2 = 300 3x^2 = 300

x 2 = 100 x^2 = 100

x = 100 x = \sqrt {100}

x = 10 x = 10

So, width = 10 m ( x ) (x) and length = 30 m ( 3 x ) (3x)

P e r i m e t e r = 2 × ( l e n g t h + w i d t h ) Perimeter = 2 \times (length + width)

= 2 × ( 30 + 10 ) = 2 \times (30 + 10)

= 2 × 40 = 2 \times 40

= 80 = \boxed{80}

Yay! Thanks for writing a solution :)

Chung Kevin - 6 years, 2 months ago

Log in to reply

You're welcome :)

Irvan Ary Maulana Nugroho - 6 years, 2 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...