Perimeter problems

$NM + LQ + HG + FE + DC = AB = 35$

$HI + JK = ML = 14$

$GF + OB = NA = 24$

$CO = DE = 7$

$IJ = QK = 4$

$Perimeter = 2AB + 2ML + 2NA + 2DE + 2IJ$

$= (2 \times 35) + (2 \times 14) + (2 \times 24) + (2 \times 7) + (2 \times 4)$

$= \boxed{168}$